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1113304012313 is a prime number
BaseRepresentation
bin10000001100110110000…
…101110001011000011001
310221102122001220121200112
4100030312011301120121
5121220021311343223
62211240024414105
7143301465652313
oct20146605613031
93842561817615
101113304012313
1139a171100399
1215b923317335
1380ca41510cc
143bc5436c7b3
151de5d955778
hex10336171619

1113304012313 has 2 divisors, whose sum is σ = 1113304012314. Its totient is φ = 1113304012312.

The previous prime is 1113304012309. The next prime is 1113304012319. The reversal of 1113304012313 is 3132104033111.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 564523817104 + 548780195209 = 751348^2 + 740797^2 .

It is a cyclic number.

It is not a de Polignac number, because 1113304012313 - 22 = 1113304012309 is a prime.

It is not a weakly prime, because it can be changed into another prime (1113304012319) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 556652006156 + 556652006157.

It is an arithmetic number, because the mean of its divisors is an integer number (556652006157).

Almost surely, 21113304012313 is an apocalyptic number.

It is an amenable number.

1113304012313 is a deficient number, since it is larger than the sum of its proper divisors (1).

1113304012313 is an equidigital number, since it uses as much as digits as its factorization.

1113304012313 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 648, while the sum is 23.

Adding to 1113304012313 its reverse (3132104033111), we get a palindrome (4245408045424).

The spelling of 1113304012313 in words is "one trillion, one hundred thirteen billion, three hundred four million, twelve thousand, three hundred thirteen".