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1113304012319 is a prime number
BaseRepresentation
bin10000001100110110000…
…101110001011000011111
310221102122001220121200202
4100030312011301120133
5121220021311343234
62211240024414115
7143301465652322
oct20146605613037
93842561817622
101113304012319
1139a1711003a4
1215b92331733b
1380ca4151105
143bc5436c7b9
151de5d95577e
hex1033617161f

1113304012319 has 2 divisors, whose sum is σ = 1113304012320. Its totient is φ = 1113304012318.

The previous prime is 1113304012313. The next prime is 1113304012349. The reversal of 1113304012319 is 9132104033111.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1113304012319 - 28 = 1113304012063 is a prime.

It is a super-2 number, since 2×11133040123192 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1113304012291 and 1113304012300.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1113304012313) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 556652006159 + 556652006160.

It is an arithmetic number, because the mean of its divisors is an integer number (556652006160).

Almost surely, 21113304012319 is an apocalyptic number.

1113304012319 is a deficient number, since it is larger than the sum of its proper divisors (1).

1113304012319 is an equidigital number, since it uses as much as digits as its factorization.

1113304012319 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1944, while the sum is 29.

The spelling of 1113304012319 in words is "one trillion, one hundred thirteen billion, three hundred four million, twelve thousand, three hundred nineteen".