Base | Representation |
---|---|
bin | 10000001100110110000… |
… | …101110001011000011011 |
3 | 10221102122001220121200121 |
4 | 100030312011301120123 |
5 | 121220021311343230 |
6 | 2211240024414111 |
7 | 143301465652315 |
oct | 20146605613033 |
9 | 3842561817617 |
10 | 1113304012315 |
11 | 39a1711003a0 |
12 | 15b923317337 |
13 | 80ca4151101 |
14 | 3bc5436c7b5 |
15 | 1de5d95577a |
hex | 1033617161b |
1113304012315 has 16 divisors (see below), whose sum is σ = 1457459225856. Its totient is φ = 809651720800.
The previous prime is 1113304012313. The next prime is 1113304012319. The reversal of 1113304012315 is 5132104033111.
It is not a de Polignac number, because 1113304012315 - 21 = 1113304012313 is a prime.
It is a super-3 number, since 3×11133040123153 (a number of 37 digits) contains 333 as substring.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 1113304012315.
It is not an unprimeable number, because it can be changed into a prime (1113304012313) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1699554 + ... + 2261656.
It is an arithmetic number, because the mean of its divisors is an integer number (91091201616).
Almost surely, 21113304012315 is an apocalyptic number.
1113304012315 is a deficient number, since it is larger than the sum of its proper divisors (344155213541).
1113304012315 is a wasteful number, since it uses less digits than its factorization.
1113304012315 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 598130.
The product of its (nonzero) digits is 1080, while the sum is 25.
Adding to 1113304012315 its reverse (5132104033111), we get a palindrome (6245408045426).
The spelling of 1113304012315 in words is "one trillion, one hundred thirteen billion, three hundred four million, twelve thousand, three hundred fifteen".
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