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11133134014200 = 233521119413321481
BaseRepresentation
bin1010001000000010001001…
…1111111000011011111000
31110102022120020210100012020
42202000202133320123320
52424401124301423300
635402254031314440
72226225303503322
oct242004237703370
943368506710166
1011133134014200
113602598a02320
1212b981407ba20
13629b086a2a53
142a6bbcd70612
151448e97348a0
hexa20227f86f8

11133134014200 has 384 divisors, whose sum is σ = 39643260883200. Its totient is φ = 2556154368000.

The previous prime is 11133134014169. The next prime is 11133134014253. The reversal of 11133134014200 is 241043133111.

It is a happy number.

It is a super-3 number, since 3×111331340142003 (a number of 40 digits) contains 333 as substring.

It is a Harshad number since it is a multiple of its sum of digits (24).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 518267460 + ... + 518288940.

It is an arithmetic number, because the mean of its divisors is an integer number (103237658550).

Almost surely, 211133134014200 is an apocalyptic number.

11133134014200 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 11133134014200, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (19821630441600).

11133134014200 is an abundant number, since it is smaller than the sum of its proper divisors (28510126869000).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11133134014200 is a wasteful number, since it uses less digits than its factorization.

11133134014200 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 25663 (or 25654 counting only the distinct ones).

The product of its (nonzero) digits is 864, while the sum is 24.

Adding to 11133134014200 its reverse (241043133111), we get a palindrome (11374177147311).

The spelling of 11133134014200 in words is "eleven trillion, one hundred thirty-three billion, one hundred thirty-four million, fourteen thousand, two hundred".