Base | Representation |
---|---|
bin | 10000001100111101110… |
… | …010010101010000011111 |
3 | 10221102222001212200111100 |
4 | 100030331302111100133 |
5 | 121220302340242421 |
6 | 2211300520124143 |
7 | 143304624324564 |
oct | 20147562252037 |
9 | 3842861780440 |
10 | 1113433134111 |
11 | 39a227a82521 |
12 | 15b95a606653 |
13 | 80cc4b1cc3c |
14 | 3bc6758086b |
15 | 1de69e5dc26 |
hex | 1033dc9541f |
1113433134111 has 24 divisors (see below), whose sum is σ = 1611174913920. Its totient is φ = 740958682176.
The previous prime is 1113433134097. The next prime is 1113433134113. The reversal of 1113433134111 is 1114313343111.
1113433134111 is a `hidden beast` number, since 1 + 1 + 1 + 343 + 313 + 4 + 1 + 1 + 1 = 666.
It is not a de Polignac number, because 1113433134111 - 27 = 1113433133983 is a prime.
It is a super-2 number, since 2×11134331341112 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1113433134113) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 60460741 + ... + 60479153.
It is an arithmetic number, because the mean of its divisors is an integer number (67132288080).
Almost surely, 21113433134111 is an apocalyptic number.
1113433134111 is a deficient number, since it is larger than the sum of its proper divisors (497741779809).
1113433134111 is a wasteful number, since it uses less digits than its factorization.
1113433134111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 30095 (or 30092 counting only the distinct ones).
The product of its digits is 1296, while the sum is 27.
Adding to 1113433134111 its reverse (1114313343111), we get a palindrome (2227746477222).
The spelling of 1113433134111 in words is "one trillion, one hundred thirteen billion, four hundred thirty-three million, one hundred thirty-four thousand, one hundred eleven".
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