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111361214453 = 651671708859
BaseRepresentation
bin110011110110110100…
…1010100011111110101
3101122102221202211120012
41213231221110133311
53311031432330303
6123054133150005
711021430463466
oct1475551243765
9348387684505
10111361214453
1143256558735
12196ba78b305
13a669518848
145565cbad6d
152d6b87a5d8
hex19eda547f5

111361214453 has 4 divisors (see below), whose sum is σ = 111362988480. Its totient is φ = 111359440428.

The previous prime is 111361214383. The next prime is 111361214479. The reversal of 111361214453 is 354412163111.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 111361214453 - 212 = 111361210357 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (111361214483) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 789263 + ... + 919596.

It is an arithmetic number, because the mean of its divisors is an integer number (27840747120).

Almost surely, 2111361214453 is an apocalyptic number.

It is an amenable number.

111361214453 is a deficient number, since it is larger than the sum of its proper divisors (1774027).

111361214453 is an equidigital number, since it uses as much as digits as its factorization.

111361214453 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1774026.

The product of its digits is 8640, while the sum is 32.

Adding to 111361214453 its reverse (354412163111), we get a palindrome (465773377564).

The spelling of 111361214453 in words is "one hundred eleven billion, three hundred sixty-one million, two hundred fourteen thousand, four hundred fifty-three".

Divisors: 1 65167 1708859 111361214453