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11138400000 = 28325571317
BaseRepresentation
bin10100101111110011…
…00111111100000000
31001202020212100100100
422113321213330000
5140302412300000
65041130322400
7543006560250
oct122771477400
931666770310
1011138400000
1147a6377862
1221aa289400
1310867c4640
14779419960
15452ccba00
hex297e67f00

11138400000 has 1296 divisors, whose sum is σ = 52310276928. Its totient is φ = 2211840000.

The previous prime is 11138399971. The next prime is 11138400061. The reversal of 11138400000 is 483111.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 143 ways as a sum of consecutive naturals, for example, 655199992 + ... + 655200008.

It is an arithmetic number, because the mean of its divisors is an integer number (40362868).

Almost surely, 211138400000 is an apocalyptic number.

11138400000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 11138400000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (26155138464).

11138400000 is an abundant number, since it is smaller than the sum of its proper divisors (41171876928).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11138400000 is an equidigital number, since it uses as much as digits as its factorization.

11138400000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 84 (or 47 counting only the distinct ones).

The product of its (nonzero) digits is 96, while the sum is 18.

Adding to 11138400000 its reverse (483111), we get a palindrome (11138883111).

The spelling of 11138400000 in words is "eleven billion, one hundred thirty-eight million, four hundred thousand".