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11143132105 = 57318375203
BaseRepresentation
bin10100110000010111…
…01011001111001001
31001202120202202120111
422120023223033021
5140310120211410
65041415554321
7543065026420
oct123013531711
931676682514
1011143132105
1147a900a096
1221ab98b9a1
1310877904c1
14779ccc2b7
15453413b8a
hex2982eb3c9

11143132105 has 8 divisors (see below), whose sum is σ = 15282009792. Its totient is φ = 7641004848.

The previous prime is 11143132097. The next prime is 11143132123. The reversal of 11143132105 is 50123134111.

It is a happy number.

11143132105 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 11143132105 - 23 = 11143132097 is a prime.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 159187567 + ... + 159187636.

It is an arithmetic number, because the mean of its divisors is an integer number (1910251224).

Almost surely, 211143132105 is an apocalyptic number.

It is an amenable number.

11143132105 is a deficient number, since it is larger than the sum of its proper divisors (4138877687).

11143132105 is an equidigital number, since it uses as much as digits as its factorization.

11143132105 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 318375215.

The product of its (nonzero) digits is 360, while the sum is 22.

Adding to 11143132105 its reverse (50123134111), we get a palindrome (61266266216).

The spelling of 11143132105 in words is "eleven billion, one hundred forty-three million, one hundred thirty-two thousand, one hundred five".

Divisors: 1 5 7 35 318375203 1591876015 2228626421 11143132105