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111432103 is a prime number
BaseRepresentation
bin1101010010001…
…01000110100111
321202200100002221
412221011012213
5212011311403
615020213211
72522104636
oct651050647
9252610087
10111432103
115799a652
123139a207
131a117173
1410b2951d
159bb1dbd
hex6a451a7

111432103 has 2 divisors, whose sum is σ = 111432104. Its totient is φ = 111432102.

The previous prime is 111432071. The next prime is 111432109. The reversal of 111432103 is 301234111.

It is a strong prime.

It is an emirp because it is prime and its reverse (301234111) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 111432103 - 25 = 111432071 is a prime.

It is a super-2 number, since 2×1114321032 = 24834227158005218, which contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (111432109) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55716051 + 55716052.

It is an arithmetic number, because the mean of its divisors is an integer number (55716052).

Almost surely, 2111432103 is an apocalyptic number.

111432103 is a deficient number, since it is larger than the sum of its proper divisors (1).

111432103 is an equidigital number, since it uses as much as digits as its factorization.

111432103 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 72, while the sum is 16.

The square root of 111432103 is about 10556.1405352525. The cubic root of 111432103 is about 481.2123620871.

Adding to 111432103 its reverse (301234111), we get a palindrome (412666214).

The spelling of 111432103 in words is "one hundred eleven million, four hundred thirty-two thousand, one hundred three".