111443414010133 has 8 divisors (see below), whose sum is σ = 115286508166680. Its totient is φ = 107600334374400.

The previous prime is 111443414010091. The next prime is 111443414010139. The reversal of 111443414010133 is 331010414344111.

It is a happy number.

It can be written as a sum of positive squares in 4 ways, for example, as 6264298168164 + 105179115841969 = 2502858^2 + 10255687^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 111443414010133 - 2²⁹ = 111442877139221 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 111443414010095 and 111443414010104.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (111443414010139) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 13326441 + ... + 20012017.

It is an arithmetic number, because the mean of its divisors is an integer number (14410813520835).

Almost surely, 2^{111443414010133} is an apocalyptic number.

It is an amenable number.

111443414010133 is a deficient number, since it is larger than the sum of its proper divisors (3843094156547).

111443414010133 is an equidigital number, since it uses as much as digits as its factorization.

111443414010133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7260407.

The product of its (nonzero) digits is 6912, while the sum is 31.

Adding to 111443414010133 its reverse (331010414344111), we get a palindrome (442453828354244).

The spelling of 111443414010133 in words is "one hundred eleven trillion, four hundred forty-three billion, four hundred fourteen million, ten thousand, one hundred thirty-three".