11200210213 has 4 divisors (see below), whose sum is σ = 11411534988. Its totient is φ = 10988885440.

The previous prime is 11200210199. The next prime is 11200210237. The reversal of 11200210213 is 31201200211.

11200210213 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 31201200211 = 439 ⋅71073349.

It can be written as a sum of positive squares in 2 ways, for example, as 5532830689 + 5667379524 = 74383^2 + 75282^2 .

It is a cyclic number.

It is not a de Polignac number, because 11200210213 - 2⁹ = 11200209701 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11200210193 and 11200210202.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11200210513) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 105662308 + ... + 105662413.

It is an arithmetic number, because the mean of its divisors is an integer number (2852883747).

Almost surely, 2^11200210213 is an apocalyptic number.

It is an amenable number.

11200210213 is a deficient number, since it is larger than the sum of its proper divisors (211324775).

11200210213 is an equidigital number, since it uses as much as digits as its factorization.

11200210213 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 211324774.

The product of its (nonzero) digits is 24, while the sum is 13.

Adding to 11200210213 its reverse (31201200211), we get a palindrome (42401410424).

The spelling of 11200210213 in words is "eleven billion, two hundred million, two hundred ten thousand, two hundred thirteen".