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11200443143 = 18397608819
BaseRepresentation
bin10100110111001100…
…10011001100000111
31001220120121110112112
422123212103030013
5140414303140033
65051224211235
7544362124121
oct123346231407
931816543475
1011200443143
1148283a378a
122207009b1b
131096608566
1478376a211
15458484c48
hex29b993307

11200443143 has 4 divisors (see below), whose sum is σ = 11201070360. Its totient is φ = 11199815928.

The previous prime is 11200443113. The next prime is 11200443151. The reversal of 11200443143 is 34134400211.

11200443143 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 11200443143 - 210 = 11200442119 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11200443113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 286013 + ... + 322806.

It is an arithmetic number, because the mean of its divisors is an integer number (2800267590).

Almost surely, 211200443143 is an apocalyptic number.

11200443143 is a deficient number, since it is larger than the sum of its proper divisors (627217).

11200443143 is an equidigital number, since it uses as much as digits as its factorization.

11200443143 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 627216.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 11200443143 its reverse (34134400211), we get a palindrome (45334843354).

The spelling of 11200443143 in words is "eleven billion, two hundred million, four hundred forty-three thousand, one hundred forty-three".

Divisors: 1 18397 608819 11200443143