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112011011120112 = 243132233731609519
BaseRepresentation
bin11001011101111110011000…
…100001110101101111110000
3112200121010222221202111020120
4121131332120201311233300
5104140142022321320422
61034121051555210240
732410346163143616
oct3135763041655760
9480533887674216
10112011011120112
113276566a724545
1210690598ba6980
134a66792b54800
141d9350cd576b6
15ce39e422945c
hex65df98875bf0

112011011120112 has 240 divisors, whose sum is σ = 327832493091840. Its totient is φ = 32878049098752.

The previous prime is 112011011120027. The next prime is 112011011120171. The reversal of 112011011120112 is 211021110110211.

It is a super-2 number, since 2×1120110111201122 (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 112011011120091 and 112011011120100.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 68788089 + ... + 70397607.

It is an arithmetic number, because the mean of its divisors is an integer number (1365968721216).

Almost surely, 2112011011120112 is an apocalyptic number.

112011011120112 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 112011011120112, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (163916246545920).

112011011120112 is an abundant number, since it is smaller than the sum of its proper divisors (215821481971728).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

112011011120112 is a wasteful number, since it uses less digits than its factorization.

112011011120112 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1609952 (or 1609933 counting only the distinct ones).

The product of its (nonzero) digits is 8, while the sum is 15.

Adding to 112011011120112 its reverse (211021110110211), we get a palindrome (323032121230323).

The spelling of 112011011120112 in words is "one hundred twelve trillion, eleven billion, eleven million, one hundred twenty thousand, one hundred twelve".