Base | Representation |
---|---|
bin | 10000010011001101100… |
… | …010111111110000111011 |
3 | 10222002021111000210022100 |
4 | 100103031202333300323 |
5 | 121323021320002230 |
6 | 2214330223354443 |
7 | 143633053622430 |
oct | 20231542776073 |
9 | 3862244023270 |
10 | 1120140000315 |
11 | 3a2059912356 |
12 | 161110752a23 |
13 | 8182349041b |
14 | 3c3021d3b87 |
15 | 1e20db73660 |
hex | 104cd8bfc3b |
1120140000315 has 24 divisors (see below), whose sum is σ = 2218944001248. Its totient is φ = 512064000000.
The previous prime is 1120140000299. The next prime is 1120140000323. The reversal of 1120140000315 is 5130000410211.
It is not a de Polignac number, because 1120140000315 - 24 = 1120140000299 is a prime.
It is a super-3 number, since 3×11201400003153 (a number of 37 digits) contains 333 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 1777999686 + ... + 1778000315.
It is an arithmetic number, because the mean of its divisors is an integer number (92456000052).
Almost surely, 21120140000315 is an apocalyptic number.
1120140000315 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
1120140000315 is a deficient number, since it is larger than the sum of its proper divisors (1098804000933).
1120140000315 is a wasteful number, since it uses less digits than its factorization.
1120140000315 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3556000019 (or 3556000016 counting only the distinct ones).
The product of its (nonzero) digits is 120, while the sum is 18.
Adding to 1120140000315 its reverse (5130000410211), we get a palindrome (6250140410526).
The spelling of 1120140000315 in words is "one trillion, one hundred twenty billion, one hundred forty million, three hundred fifteen", and thus it is an aban number.
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