Base | Representation |
---|---|
bin | 10000010011010001001… |
… | …011101100100011110111 |
3 | 10222002102201210221210122 |
4 | 100103101023230203313 |
5 | 121323132424014312 |
6 | 2214340243042155 |
7 | 143634424255541 |
oct | 20232113544367 |
9 | 3862381727718 |
10 | 1120201001207 |
11 | 3a2090297212 |
12 | 16112907035b |
13 | 81832ccab22 |
14 | 3c30a352691 |
15 | 1e2141c2b72 |
hex | 104d12ec8f7 |
1120201001207 has 2 divisors, whose sum is σ = 1120201001208. Its totient is φ = 1120201001206.
The previous prime is 1120201001201. The next prime is 1120201001209. The reversal of 1120201001207 is 7021001020211.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1120201001207 - 210 = 1120201000183 is a prime.
Together with 1120201001209, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1120201001201) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 560100500603 + 560100500604.
It is an arithmetic number, because the mean of its divisors is an integer number (560100500604).
Almost surely, 21120201001207 is an apocalyptic number.
1120201001207 is a deficient number, since it is larger than the sum of its proper divisors (1).
1120201001207 is an equidigital number, since it uses as much as digits as its factorization.
1120201001207 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 56, while the sum is 17.
Adding to 1120201001207 its reverse (7021001020211), we get a palindrome (8141202021418).
The spelling of 1120201001207 in words is "one trillion, one hundred twenty billion, two hundred one million, one thousand, two hundred seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.064 sec. • engine limits •