11202102020141 has 2 divisors, whose sum is σ = 11202102020142. Its totient is φ = 11202102020140.

The previous prime is 11202102020077. The next prime is 11202102020143. The reversal of 11202102020141 is 14102020120211.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10699087734916 + 503014285225 = 3270946^2 + 709235^2 .

It is a cyclic number.

It is not a de Polignac number, because 11202102020141 - 2⁶ = 11202102020077 is a prime.

Together with 11202102020143, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11202102020143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5601051010070 + 5601051010071.

It is an arithmetic number, because the mean of its divisors is an integer number (5601051010071).

Almost surely, 2^{11202102020141} is an apocalyptic number.

It is an amenable number.

11202102020141 is a deficient number, since it is larger than the sum of its proper divisors (1).

11202102020141 is an equidigital number, since it uses as much as digits as its factorization.

11202102020141 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 64, while the sum is 17.

Adding to 11202102020141 its reverse (14102020120211), we get a palindrome (25304122140352).

The spelling of 11202102020141 in words is "eleven trillion, two hundred two billion, one hundred two million, twenty thousand, one hundred forty-one".