11203012124231 has 2 divisors, whose sum is σ = 11203012124232. Its totient is φ = 11203012124230.

The previous prime is 11203012124141. The next prime is 11203012124233. The reversal of 11203012124231 is 13242121030211.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11203012124231 is a prime.

It is a super-3 number, since 3×11203012124231³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

Together with 11203012124233, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 11203012124197 and 11203012124206.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11203012124233) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5601506062115 + 5601506062116.

It is an arithmetic number, because the mean of its divisors is an integer number (5601506062116).

Almost surely, 2^{11203012124231} is an apocalyptic number.

11203012124231 is a deficient number, since it is larger than the sum of its proper divisors (1).

11203012124231 is an equidigital number, since it uses as much as digits as its factorization.

11203012124231 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 576, while the sum is 23.

Adding to 11203012124231 its reverse (13242121030211), we get a palindrome (24445133154442).

The spelling of 11203012124231 in words is "eleven trillion, two hundred three billion, twelve million, one hundred twenty-four thousand, two hundred thirty-one".