112031310401 has 2 divisors, whose sum is σ = 112031310402. Its totient is φ = 112031310400.

The previous prime is 112031310379. The next prime is 112031310403. The reversal of 112031310401 is 104013130211.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 110040812176 + 1990498225 = 331724^2 + 44615^2 .

It is an emirp because it is prime and its reverse (104013130211) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 112031310401 - 2¹⁴ = 112031294017 is a prime.

Together with 112031310403, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 112031310401.

It is not a weakly prime, because it can be changed into another prime (112031310403) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56015655200 + 56015655201.

It is an arithmetic number, because the mean of its divisors is an integer number (56015655201).

Almost surely, 2^112031310401 is an apocalyptic number.

It is an amenable number.

112031310401 is a deficient number, since it is larger than the sum of its proper divisors (1).

112031310401 is an equidigital number, since it uses as much as digits as its factorization.

112031310401 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 112031310401 its reverse (104013130211), we get a palindrome (216044440612).

The spelling of 112031310401 in words is "one hundred twelve billion, thirty-one million, three hundred ten thousand, four hundred one".