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1121003122130 = 25112100312213
BaseRepresentation
bin10000010100000000111…
…111100010110111010010
310222011111122010220211222
4100110000333202313102
5121331303244402010
62214552015205042
7143663334214523
oct20240077426722
93864448126758
101121003122130
113a2462046571
12161311816782
13819302441a8
143c384ab084a
151e25e818355
hex10500fe2dd2

1121003122130 has 8 divisors (see below), whose sum is σ = 2017805619852. Its totient is φ = 448401248848.

The previous prime is 1121003122073. The next prime is 1121003122153. The reversal of 1121003122130 is 312213001211.

It can be written as a sum of positive squares in 2 ways, for example, as 1119996773401 + 1006348729 = 1058299^2 + 31723^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a junction number, because it is equal to n+sod(n) for n = 1121003122099 and 1121003122108.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 56050156097 + ... + 56050156116.

Almost surely, 21121003122130 is an apocalyptic number.

1121003122130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

1121003122130 is a deficient number, since it is larger than the sum of its proper divisors (896802497722).

1121003122130 is a wasteful number, since it uses less digits than its factorization.

1121003122130 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 112100312220.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 1121003122130 its reverse (312213001211), we get a palindrome (1433216123341).

The spelling of 1121003122130 in words is "one trillion, one hundred twenty-one billion, three million, one hundred twenty-two thousand, one hundred thirty".

Divisors: 1 2 5 10 112100312213 224200624426 560501561065 1121003122130