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112102201211000 = 235371113990111311
BaseRepresentation
bin11001011111010011010011…
…111000011011100001111000
3112200220212101011000002011012
4121133103103320123201320
5104143140302002223000
61034231012411253052
732420055023135120
oct3137232370334170
9480825334002135
10112102201211000
11327a03050a3520
12106a61a844a188
134a722663abb80
141d97abdd25c80
15ce607ecd5735
hex65f4d3e1b878

112102201211000 has 512 divisors, whose sum is σ = 352271448023040. Its totient is φ = 32247072000000.

The previous prime is 112102201210981. The next prime is 112102201211027. The reversal of 112102201211000 is 112102201211.

It is a Harshad number since it is a multiple of its sum of digits (14).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 9910895345 + ... + 9910906655.

It is an arithmetic number, because the mean of its divisors is an integer number (688030171920).

Almost surely, 2112102201211000 is an apocalyptic number.

112102201211000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 112102201211000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (176135724011520).

112102201211000 is an abundant number, since it is smaller than the sum of its proper divisors (240169246812040).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

112102201211000 is a wasteful number, since it uses less digits than its factorization.

112102201211000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 21264 (or 21250 counting only the distinct ones).

The product of its (nonzero) digits is 16, while the sum is 14.

Adding to 112102201211000 its reverse (112102201211), we get a palindrome (112214303412211).

112102201211000 divided by its reverse (112102201211) gives a cube (1000 = 103).

It can be divided in two parts, 112102 and 201211000, that added together give a palindrome (201323102).

The spelling of 112102201211000 in words is "one hundred twelve trillion, one hundred two billion, two hundred one million, two hundred eleven thousand".