Base | Representation |
---|---|
bin | 110100001101001010… |
… | …1111100011110100101 |
3 | 101201101012211110221022 |
4 | 1220122111330132211 |
5 | 3314100421010203 |
6 | 123300402100525 |
7 | 11046134466155 |
oct | 1503225743645 |
9 | 351335743838 |
10 | 112111110053 |
11 | 43600887368 |
12 | 1988994a745 |
13 | a7589a7957 |
14 | 55d7722765 |
15 | 2db2606a38 |
hex | 1a1a57c7a5 |
112111110053 has 2 divisors, whose sum is σ = 112111110054. Its totient is φ = 112111110052.
The previous prime is 112111110019. The next prime is 112111110061. The reversal of 112111110053 is 350011111211.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 79173578884 + 32937531169 = 281378^2 + 181487^2 .
It is a cyclic number.
It is not a de Polignac number, because 112111110053 - 212 = 112111105957 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (112111110253) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56055555026 + 56055555027.
It is an arithmetic number, because the mean of its divisors is an integer number (56055555027).
Almost surely, 2112111110053 is an apocalyptic number.
It is an amenable number.
112111110053 is a deficient number, since it is larger than the sum of its proper divisors (1).
112111110053 is an equidigital number, since it uses as much as digits as its factorization.
112111110053 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 30, while the sum is 17.
Adding to 112111110053 its reverse (350011111211), we get a palindrome (462122221264).
The spelling of 112111110053 in words is "one hundred twelve billion, one hundred eleven million, one hundred ten thousand, fifty-three".
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