Base | Representation |
---|---|
bin | 1010001100100100111110… |
… | …0110000001101101100111 |
3 | 1110200210001210201212201011 |
4 | 2203021033212001231213 |
5 | 2432141014200323421 |
6 | 35502204300443051 |
7 | 2234660662515052 |
oct | 243111746015547 |
9 | 43623053655634 |
10 | 11211200011111 |
11 | 3632709149241 |
12 | 1310980249487 |
13 | 634299c29c29 |
14 | 2aa8a6d0da99 |
15 | 14696802a4e1 |
hex | a324f981b67 |
11211200011111 has 2 divisors, whose sum is σ = 11211200011112. Its totient is φ = 11211200011110.
The previous prime is 11211200011097. The next prime is 11211200011229. The reversal of 11211200011111 is 11111000211211.
11211200011111 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11211200011111 - 241 = 9012176755559 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11211200011091 and 11211200011100.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11211200018111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5605600005555 + 5605600005556.
It is an arithmetic number, because the mean of its divisors is an integer number (5605600005556).
Almost surely, 211211200011111 is an apocalyptic number.
11211200011111 is a deficient number, since it is larger than the sum of its proper divisors (1).
11211200011111 is an equidigital number, since it uses as much as digits as its factorization.
11211200011111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4, while the sum is 13.
Adding to 11211200011111 its reverse (11111000211211), we get a palindrome (22322200222322).
The spelling of 11211200011111 in words is "eleven trillion, two hundred eleven billion, two hundred million, eleven thousand, one hundred eleven".
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