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11212100201120 = 2557132377343313
BaseRepresentation
bin1010001100101000010100…
…1111111110101010100000
31110200212101112121021020212
42203022011033332222200
52432144340122413440
635502433454553252
72235022203144530
oct243120517765240
943625345537225
1011212100201120
1136330302a0325
121310b91808828
136343b158bc40
142aa9506b94c0
151469bc093465
hexa32853feaa0

11212100201120 has 384 divisors, whose sum is σ = 34063582178304. Its totient is φ = 3389695524864.

The previous prime is 11212100201101. The next prime is 11212100201161. The reversal of 11212100201120 is 2110200121211.

It is a super-2 number, since 2×112121002011202 (a number of 27 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (14).

It is a junction number, because it is equal to n+sod(n) for n = 11212100201095 and 11212100201104.

It is an unprimeable number.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 258840584 + ... + 258883896.

It is an arithmetic number, because the mean of its divisors is an integer number (88707245256).

Almost surely, 211212100201120 is an apocalyptic number.

11212100201120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 11212100201120, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (17031791089152).

11212100201120 is an abundant number, since it is smaller than the sum of its proper divisors (22851481977184).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11212100201120 is a wasteful number, since it uses less digits than its factorization.

11212100201120 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 44144 (or 44136 counting only the distinct ones).

The product of its (nonzero) digits is 16, while the sum is 14.

Adding to 11212100201120 its reverse (2110200121211), we get a palindrome (13322300322331).

The spelling of 11212100201120 in words is "eleven trillion, two hundred twelve billion, one hundred million, two hundred one thousand, one hundred twenty".