Base | Representation |
---|---|
bin | 1010001100101000010101… |
… | …0011011010001001001111 |
3 | 1110200212101121021221102211 |
4 | 2203022011103122021033 |
5 | 2432144340340200421 |
6 | 35502433530131251 |
7 | 2235022213610512 |
oct | 243120523321117 |
9 | 43625347257384 |
10 | 11212101100111 |
11 | 363303085479a |
12 | 1310b91b80b27 |
13 | 6343b18151a2 |
14 | 2aa950870d79 |
15 | 1469bc1be9e1 |
hex | a32854da24f |
11212101100111 has 2 divisors, whose sum is σ = 11212101100112. Its totient is φ = 11212101100110.
The previous prime is 11212101100097. The next prime is 11212101100163. The reversal of 11212101100111 is 11100110121211.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11212101100111 - 217 = 11212100969039 is a prime.
It is a super-2 number, since 2×112121011001112 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 11212101100091 and 11212101100100.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11212101100511) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5606050550055 + 5606050550056.
It is an arithmetic number, because the mean of its divisors is an integer number (5606050550056).
Almost surely, 211212101100111 is an apocalyptic number.
11212101100111 is a deficient number, since it is larger than the sum of its proper divisors (1).
11212101100111 is an equidigital number, since it uses as much as digits as its factorization.
11212101100111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4, while the sum is 13.
Adding to 11212101100111 its reverse (11100110121211), we get a palindrome (22312211221322).
The spelling of 11212101100111 in words is "eleven trillion, two hundred twelve billion, one hundred one million, one hundred thousand, one hundred eleven".
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