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11212211147 is a prime number
BaseRepresentation
bin10100111000100110…
…01100001111001011
31001221101202100012112
422130103030033023
5140430311224042
65052324332535
7544564136144
oct123423141713
931841670175
1011212211147
114834001205
12220ab4414b
131098b98a87
14785150acb
1545950b982
hex29c4cc3cb

11212211147 has 2 divisors, whose sum is σ = 11212211148. Its totient is φ = 11212211146.

The previous prime is 11212211113. The next prime is 11212211149. The reversal of 11212211147 is 74111221211.

11212211147 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 11212211147 - 216 = 11212145611 is a prime.

It is a super-2 number, since 2×112122111472 (a number of 21 digits) contains 22 as substring.

Together with 11212211149, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (11212211149) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5606105573 + 5606105574.

It is an arithmetic number, because the mean of its divisors is an integer number (5606105574).

Almost surely, 211212211147 is an apocalyptic number.

11212211147 is a deficient number, since it is larger than the sum of its proper divisors (1).

11212211147 is an equidigital number, since it uses as much as digits as its factorization.

11212211147 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 224, while the sum is 23.

Adding to 11212211147 its reverse (74111221211), we get a palindrome (85323432358).

The spelling of 11212211147 in words is "eleven billion, two hundred twelve million, two hundred eleven thousand, one hundred forty-seven".