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11212313003100 = 2232521123190125903
BaseRepresentation
bin1010001100101001000111…
…1011110000010001011100
31110200212221101000201200200
42203022101323300101130
52432200304112044400
635502510540023500
72235030366011466
oct243122173602134
943625841021620
1011212313003100
11363312a427630
121311030b31b90
136344166a9281
142aa970a71136
151469d0acab00
hexa3291ef045c

11212313003100 has 432 divisors, whose sum is σ = 40028831990784. Its totient is φ = 2598488640000.

The previous prime is 11212313003083. The next prime is 11212313003117. The reversal of 11212313003100 is 130031321211.

11212313003100 is a `hidden beast` number, since 1 + 1 + 21 + 2 + 31 + 300 + 310 + 0 = 666.

It is an interprime number because it is at equal distance from previous prime (11212313003083) and next prime (11212313003117).

It is a super-2 number, since 2×112123130031002 (a number of 27 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 143 ways as a sum of consecutive naturals, for example, 432844749 + ... + 432870651.

It is an arithmetic number, because the mean of its divisors is an integer number (92659333312).

Almost surely, 211212313003100 is an apocalyptic number.

11212313003100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 11212313003100, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (20014415995392).

11212313003100 is an abundant number, since it is smaller than the sum of its proper divisors (28816518987684).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11212313003100 is a wasteful number, since it uses less digits than its factorization.

11212313003100 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 27858 (or 27848 counting only the distinct ones).

The product of its (nonzero) digits is 108, while the sum is 18.

Adding to 11212313003100 its reverse (130031321211), we get a palindrome (11342344324311).

The spelling of 11212313003100 in words is "eleven trillion, two hundred twelve billion, three hundred thirteen million, three thousand, one hundred".