Base | Representation |
---|---|
bin | 11001011111100110110011… |
… | …011010011011101111010110 |
3 | 112200222212101210200102122020 |
4 | 121133212303122123233112 |
5 | 104144011133104004420 |
6 | 1034244353324114010 |
7 | 32421425501103021 |
oct | 3137466332335726 |
9 | 480885353612566 |
10 | 112123131313110 |
11 | 327a9175644a75 |
12 | 106aa269995906 |
13 | 4a7422068c788 |
14 | 1d98b079621b8 |
15 | ce68a7527340 |
hex | 65f9b369bbd6 |
112123131313110 has 32 divisors (see below), whose sum is σ = 269095937212512. Its totient is φ = 29899454787840.
The previous prime is 112123131313099. The next prime is 112123131313111. The reversal of 112123131313110 is 11313131321211.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (112123131313111) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 19272442 + ... + 24406418.
It is an arithmetic number, because the mean of its divisors is an integer number (8409248037891).
Almost surely, 2112123131313110 is an apocalyptic number.
112123131313110 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
112123131313110 is an abundant number, since it is smaller than the sum of its proper divisors (156972805899402).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
112123131313110 is a wasteful number, since it uses less digits than its factorization.
112123131313110 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5861968.
The product of its (nonzero) digits is 324, while the sum is 24.
Adding to 112123131313110 its reverse (11313131321211), we get a palindrome (123436262634321).
The spelling of 112123131313110 in words is "one hundred twelve trillion, one hundred twenty-three billion, one hundred thirty-one million, three hundred thirteen thousand, one hundred ten".
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