Base | Representation |
---|---|
bin | 1010001100101100001000… |
… | …1010010101010100001011 |
3 | 1110200222000202112200210111 |
4 | 2203023002022111110023 |
5 | 2432203433231144321 |
6 | 35503123122255151 |
7 | 2235056422333540 |
oct | 243130212252413 |
9 | 43628022480714 |
10 | 11213122131211 |
11 | 3633505132550 |
12 | 1311217ab74b7 |
13 | 634515206bc0 |
14 | 2aaa0a2d4bc7 |
15 | 146a2bb575e1 |
hex | a32c229550b |
11213122131211 has 32 divisors (see below), whose sum is σ = 15940991420928. Its totient is φ = 7590948272640.
The previous prime is 11213122131199. The next prime is 11213122131221.
11213122131211 is nontrivially palindromic in base 10.
It is a cyclic number.
It is not a de Polignac number, because 11213122131211 - 29 = 11213122130699 is a prime.
It is not an unprimeable number, because it can be changed into a prime (11213122131221) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 329451225 + ... + 329485258.
It is an arithmetic number, because the mean of its divisors is an integer number (498155981904).
Almost surely, 211213122131211 is an apocalyptic number.
11213122131211 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
11213122131211 is a deficient number, since it is larger than the sum of its proper divisors (4727869289717).
11213122131211 is a wasteful number, since it uses less digits than its factorization.
11213122131211 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 658936531.
The product of its digits is 144, while the sum is 22.
Multiplying 11213122131211 by its sum of digits (22), we get a palindrome (246688686886642).
It can be divided in two parts, 1121312 and 2131211, that added together give a palindrome (3252523).
The spelling of 11213122131211 in words is "eleven trillion, two hundred thirteen billion, one hundred twenty-two million, one hundred thirty-one thousand, two hundred eleven".
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