Base | Representation |
---|---|
bin | 11001011111110000001101… |
… | …000111011100110111111010 |
3 | 112201000211110100000212222111 |
4 | 121133300031013130313322 |
5 | 104144142321403033200 |
6 | 1034253143141042534 |
7 | 32422233610311346 |
oct | 3137601507346772 |
9 | 481024410025874 |
10 | 112133226221050 |
11 | 328024859927a1 |
12 | 106b02066b644a |
13 | 4a7516bc29a98 |
14 | 1d993c454c626 |
15 | ce6c988d10ba |
hex | 65fc0d1dcdfa |
112133226221050 has 48 divisors (see below), whose sum is σ = 220972732377912. Its totient is φ = 42188818636800.
The previous prime is 112133226220969. The next prime is 112133226221053. The reversal of 112133226221050 is 50122622331211.
It is a happy number.
It can be written as a sum of positive squares in 12 ways, for example, as 17318390202369 + 94814836018681 = 4161537^2 + 9737291^2 .
It is not an unprimeable number, because it can be changed into a prime (112133226221053) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 39313527 + ... + 42069226.
Almost surely, 2112133226221050 is an apocalyptic number.
112133226221050 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
112133226221050 is a deficient number, since it is larger than the sum of its proper divisors (108839506156862).
112133226221050 is a wasteful number, since it uses less digits than its factorization.
112133226221050 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 81384403 (or 81384398 counting only the distinct ones).
The product of its (nonzero) digits is 8640, while the sum is 31.
Adding to 112133226221050 its reverse (50122622331211), we get a palindrome (162255848552261).
The spelling of 112133226221050 in words is "one hundred twelve trillion, one hundred thirty-three billion, two hundred twenty-six million, two hundred twenty-one thousand, fifty".
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