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11213410300 = 2252112134103
BaseRepresentation
bin10100111000101111…
…10000111111111100
31001221111000021010121
422130113300333330
5140431113112200
65052410144324
7544610262211
oct123427607774
931844007117
1011213410300
114834750144
12220b4220a4
1310991c8831
14785383b08
15459696e1a
hex29c5f0ffc

11213410300 has 18 divisors (see below), whose sum is σ = 24333100568. Its totient is φ = 4485364080.

The previous prime is 11213410297. The next prime is 11213410301. The reversal of 11213410300 is 301431211.

It is a super-2 number, since 2×112134103002 (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11213410301) by changing a digit.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 56066952 + ... + 56067151.

Almost surely, 211213410300 is an apocalyptic number.

11213410300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

11213410300 is an abundant number, since it is smaller than the sum of its proper divisors (13119690268).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11213410300 is a wasteful number, since it uses less digits than its factorization.

11213410300 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 112134117 (or 112134110 counting only the distinct ones).

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 11213410300 its reverse (301431211), we get a palindrome (11514841511).

The spelling of 11213410300 in words is "eleven billion, two hundred thirteen million, four hundred ten thousand, three hundred".

Divisors: 1 2 4 5 10 20 25 50 100 112134103 224268206 448536412 560670515 1121341030 2242682060 2803352575 5606705150 11213410300