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11213433232055 = 52242686646411
BaseRepresentation
bin1010001100101101010010…
…1101000101101010110111
31110200222211102221020220222
42203023110231011222313
52432210102401411210
635503214034244555
72235100220546225
oct243132455055267
943628742836828
1011213433232055
1136336547a918a
1213112a412675b
136345647c0642
142aaa39757b15
15146a4910a655
hexa32d4b45ab7

11213433232055 has 4 divisors (see below), whose sum is σ = 13456119878472. Its totient is φ = 8970746585640.

The previous prime is 11213433232049. The next prime is 11213433232081. The reversal of 11213433232055 is 55023233431211.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 11213433232055 - 28 = 11213433231799 is a prime.

It is a Duffinian number.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1121343323201 + ... + 1121343323210.

It is an arithmetic number, because the mean of its divisors is an integer number (3364029969618).

Almost surely, 211213433232055 is an apocalyptic number.

11213433232055 is a deficient number, since it is larger than the sum of its proper divisors (2242686646417).

11213433232055 is an equidigital number, since it uses as much as digits as its factorization.

11213433232055 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2242686646416.

The product of its (nonzero) digits is 64800, while the sum is 35.

Adding to 11213433232055 its reverse (55023233431211), we get a palindrome (66236666663266).

The spelling of 11213433232055 in words is "eleven trillion, two hundred thirteen billion, four hundred thirty-three million, two hundred thirty-two thousand, fifty-five".

Divisors: 1 5 2242686646411 11213433232055