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1122212402021 is a prime number
BaseRepresentation
bin10000010101001001000…
…100100101001101100101
310222021121220121201000002
4100111021010211031211
5121341242333331041
62215312014231045
7144035320013054
oct20251104451545
93867556551002
101122212402021
113a2a22710437
121615aa7b5485
1381a93937519
143c45b53839b
151e2d0a8859b
hex10549125365

1122212402021 has 2 divisors, whose sum is σ = 1122212402022. Its totient is φ = 1122212402020.

The previous prime is 1122212401997. The next prime is 1122212402023. The reversal of 1122212402021 is 1202042122211.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 865432041796 + 256780360225 = 930286^2 + 506735^2 .

It is a cyclic number.

It is not a de Polignac number, because 1122212402021 - 26 = 1122212401957 is a prime.

Together with 1122212402023, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 1122212401984 and 1122212402002.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1122212402023) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 561106201010 + 561106201011.

It is an arithmetic number, because the mean of its divisors is an integer number (561106201011).

Almost surely, 21122212402021 is an apocalyptic number.

It is an amenable number.

1122212402021 is a deficient number, since it is larger than the sum of its proper divisors (1).

1122212402021 is an equidigital number, since it uses as much as digits as its factorization.

1122212402021 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 256, while the sum is 20.

Adding to 1122212402021 its reverse (1202042122211), we get a palindrome (2324254524232).

The spelling of 1122212402021 in words is "one trillion, one hundred twenty-two billion, two hundred twelve million, four hundred two thousand, twenty-one".