1122413031445 has 4 divisors (see below), whose sum is σ = 1346895637740. Its totient is φ = 897930425152.

The previous prime is 1122413031433. The next prime is 1122413031497. The reversal of 1122413031445 is 5441303142211.

It is a happy number.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 379384547364 + 743028484081 = 615942^2 + 861991^2 .

It is a cyclic number.

It is not a de Polignac number, because 1122413031445 - 2⁹ = 1122413030933 is a prime.

It is a super-3 number, since 3×1122413031445³ (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 112241303140 + ... + 112241303149.

It is an arithmetic number, because the mean of its divisors is an integer number (336723909435).

Almost surely, 2^{1122413031445} is an apocalyptic number.

It is an amenable number.

1122413031445 is a deficient number, since it is larger than the sum of its proper divisors (224482606295).

1122413031445 is an equidigital number, since it uses as much as digits as its factorization.

1122413031445 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 224482606294.

The product of its (nonzero) digits is 11520, while the sum is 31.

Adding to 1122413031445 its reverse (5441303142211), we get a palindrome (6563716173656).

The spelling of 1122413031445 in words is "one trillion, one hundred twenty-two billion, four hundred thirteen million, thirty-one thousand, four hundred forty-five".