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11224331201 = 25144718451
BaseRepresentation
bin10100111010000010…
…11011001111000001
31001222020120002210102
422131001123033001
5140441412044301
65053440212145
7545102145446
oct123501331701
931866502712
1011224331201
11483a92a186
12221300a055
13109b5505c5
147869c79cd
1545a602b6b
hex29d05b3c1

11224331201 has 4 divisors (see below), whose sum is σ = 11269049904. Its totient is φ = 11179612500.

The previous prime is 11224331191. The next prime is 11224331213. The reversal of 11224331201 is 10213342211.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 10213342211 = 23444058357.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11224331201 is a prime.

It is a super-2 number, since 2×112243312012 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11224331801) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22358975 + ... + 22359476.

It is an arithmetic number, because the mean of its divisors is an integer number (2817262476).

Almost surely, 211224331201 is an apocalyptic number.

It is an amenable number.

11224331201 is a deficient number, since it is larger than the sum of its proper divisors (44718703).

11224331201 is an equidigital number, since it uses as much as digits as its factorization.

11224331201 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 44718702.

The product of its (nonzero) digits is 288, while the sum is 20.

Adding to 11224331201 its reverse (10213342211), we get a palindrome (21437673412).

The spelling of 11224331201 in words is "eleven billion, two hundred twenty-four million, three hundred thirty-one thousand, two hundred one".

Divisors: 1 251 44718451 11224331201