11230011313207 has 2 divisors, whose sum is σ = 11230011313208. Its totient is φ = 11230011313206.

The previous prime is 11230011313163. The next prime is 11230011313223. The reversal of 11230011313207 is 70231311003211.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11230011313207 is a prime.

It is a super-2 number, since 2×11230011313207² (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11230011313307) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5615005656603 + 5615005656604.

It is an arithmetic number, because the mean of its divisors is an integer number (5615005656604).

Almost surely, 2^{11230011313207} is an apocalyptic number.

11230011313207 is a deficient number, since it is larger than the sum of its proper divisors (1).

11230011313207 is an equidigital number, since it uses as much as digits as its factorization.

11230011313207 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 756, while the sum is 25.

Adding to 11230011313207 its reverse (70231311003211), we get a palindrome (81461322316418).

The spelling of 11230011313207 in words is "eleven trillion, two hundred thirty billion, eleven million, three hundred thirteen thousand, two hundred seven".