Base | Representation |
---|---|
bin | 1010001101101011000011… |
… | …0101011100110001000111 |
3 | 1110202120121210112001000012 |
4 | 2203122300311130301013 |
5 | 2432443030344010343 |
6 | 35514555044140435 |
7 | 2236225102115333 |
oct | 243326065346107 |
9 | 43676553461005 |
10 | 11230011313223 |
11 | 363a691690a0a |
12 | 131455009771b |
13 | 635ca7269821 |
14 | 2ab76d3a87c3 |
15 | 1471b973e718 |
hex | a36b0d5cc47 |
11230011313223 has 2 divisors, whose sum is σ = 11230011313224. Its totient is φ = 11230011313222.
The previous prime is 11230011313207. The next prime is 11230011313273. The reversal of 11230011313223 is 32231311003211.
11230011313223 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11230011313223 - 24 = 11230011313207 is a prime.
It is a super-2 number, since 2×112300113132232 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11230011313273) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5615005656611 + 5615005656612.
It is an arithmetic number, because the mean of its divisors is an integer number (5615005656612).
Almost surely, 211230011313223 is an apocalyptic number.
11230011313223 is a deficient number, since it is larger than the sum of its proper divisors (1).
11230011313223 is an equidigital number, since it uses as much as digits as its factorization.
11230011313223 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 648, while the sum is 23.
Adding to 11230011313223 its reverse (32231311003211), we get a palindrome (43461322316434).
The spelling of 11230011313223 in words is "eleven trillion, two hundred thirty billion, eleven million, three hundred thirteen thousand, two hundred twenty-three".
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