Base | Representation |
---|---|
bin | 10000010101111001010… |
… | …010010111101101111101 |
3 | 10222100201021202011011021 |
4 | 100111321102113231331 |
5 | 121344421424320013 |
6 | 2215524152224141 |
7 | 144064341513463 |
oct | 20257122275575 |
9 | 3870637664137 |
10 | 1123021323133 |
11 | 3a32a8294886 |
12 | 16179569b051 |
13 | 81b923c1b78 |
14 | 3c4d6b46833 |
15 | 1e32bac3a8d |
hex | 10579497b7d |
1123021323133 has 2 divisors, whose sum is σ = 1123021323134. Its totient is φ = 1123021323132.
The previous prime is 1123021323131. The next prime is 1123021323143. The reversal of 1123021323133 is 3313231203211.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1121858035684 + 1163287449 = 1059178^2 + 34107^2 .
It is a cyclic number.
It is not a de Polignac number, because 1123021323133 - 21 = 1123021323131 is a prime.
It is a super-2 number, since 2×11230213231332 (a number of 25 digits) contains 22 as substring.
Together with 1123021323131, it forms a pair of twin primes.
It is a junction number, because it is equal to n+sod(n) for n = 1123021323098 and 1123021323107.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1123021323131) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 561510661566 + 561510661567.
It is an arithmetic number, because the mean of its divisors is an integer number (561510661567).
Almost surely, 21123021323133 is an apocalyptic number.
It is an amenable number.
1123021323133 is a deficient number, since it is larger than the sum of its proper divisors (1).
1123021323133 is an equidigital number, since it uses as much as digits as its factorization.
1123021323133 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1944, while the sum is 25.
Adding to 1123021323133 its reverse (3313231203211), we get a palindrome (4436252526344).
The spelling of 1123021323133 in words is "one trillion, one hundred twenty-three billion, twenty-one million, three hundred twenty-three thousand, one hundred thirty-three".
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