Base | Representation |
---|---|
bin | 100001011110001… |
… | …0111011111111011 |
3 | 2220021100110120112 |
4 | 1002330113133323 |
5 | 4300004334042 |
6 | 303240214535 |
7 | 36555241451 |
oct | 10274273773 |
9 | 2807313515 |
10 | 1123121147 |
11 | 526a775a5 |
12 | 27416a44b |
13 | 14b8b7935 |
14 | a923a9d1 |
15 | 68901982 |
hex | 42f177fb |
1123121147 has 2 divisors, whose sum is σ = 1123121148. Its totient is φ = 1123121146.
The previous prime is 1123121143. The next prime is 1123121149. The reversal of 1123121147 is 7411213211.
It is a strong prime.
It is an emirp because it is prime and its reverse (7411213211) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1123121147 - 22 = 1123121143 is a prime.
It is a super-2 number, since 2×11231211472 = 2522802221677191218, which contains 22 as substring.
Together with 1123121149, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (1123121143) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 561560573 + 561560574.
It is an arithmetic number, because the mean of its divisors is an integer number (561560574).
Almost surely, 21123121147 is an apocalyptic number.
1123121147 is a deficient number, since it is larger than the sum of its proper divisors (1).
1123121147 is an equidigital number, since it uses as much as digits as its factorization.
1123121147 is an evil number, because the sum of its binary digits is even.
The product of its digits is 336, while the sum is 23.
The square root of 1123121147 is about 33512.9996717692. Note that the first 3 decimals coincide. The cubic root of 1123121147 is about 1039.4626005007.
Adding to 1123121147 its reverse (7411213211), we get a palindrome (8534334358).
The spelling of 1123121147 in words is "one billion, one hundred twenty-three million, one hundred twenty-one thousand, one hundred forty-seven".
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