Base | Representation |
---|---|
bin | 110100010011011001… |
… | …0111010011001111010 |
3 | 101201220202221201200100 |
4 | 1220212302322121322 |
5 | 3320012411432310 |
6 | 123333224020230 |
7 | 11054252335164 |
oct | 1504662723172 |
9 | 351822851610 |
10 | 112320030330 |
11 | 436a8802252 |
12 | 19927901676 |
13 | a790066211 |
14 | 5617387934 |
15 | 2dc5b23ec0 |
hex | 1a26cba67a |
112320030330 has 24 divisors (see below), whose sum is σ = 292032079092. Its totient is φ = 29952008064.
The previous prime is 112320030311. The next prime is 112320030331. The reversal of 112320030330 is 33030023211.
112320030330 is a `hidden beast` number, since 1 + 12 + 320 + 0 + 3 + 0 + 330 = 666.
It can be written as a sum of positive squares in 2 ways, for example, as 111795940881 + 524089449 = 334359^2 + 22893^2 .
It is a Harshad number since it is a multiple of its sum of digits (18).
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (112320030331) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 624000079 + ... + 624000258.
Almost surely, 2112320030330 is an apocalyptic number.
112320030330 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
112320030330 is an abundant number, since it is smaller than the sum of its proper divisors (179712048762).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
112320030330 is a wasteful number, since it uses less digits than its factorization.
112320030330 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1248000350 (or 1248000347 counting only the distinct ones).
The product of its (nonzero) digits is 324, while the sum is 18.
Adding to 112320030330 its reverse (33030023211), we get a palindrome (145350053541).
The spelling of 112320030330 in words is "one hundred twelve billion, three hundred twenty million, thirty thousand, three hundred thirty".
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