Base | Representation |
---|---|
bin | 11001100010100111101011… |
… | …100100110110111001000111 |
3 | 112201201122222000011101110121 |
4 | 121202213223210312321013 |
5 | 104210404303343000241 |
6 | 1034523443550402411 |
7 | 32442406602642211 |
oct | 3142475344667107 |
9 | 481648860141417 |
10 | 112330232000071 |
11 | 32878a905803a8 |
12 | 10722427500407 |
13 | 4a8a906b08c67 |
14 | 1da4b52acd5b1 |
15 | cebe79053ad1 |
hex | 6629eb936e47 |
112330232000071 has 2 divisors, whose sum is σ = 112330232000072. Its totient is φ = 112330232000070.
The previous prime is 112330232000069. The next prime is 112330232000081. The reversal of 112330232000071 is 170000232033211.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 112330232000071 - 21 = 112330232000069 is a prime.
Together with 112330232000069, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (112330232000081) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56165116000035 + 56165116000036.
It is an arithmetic number, because the mean of its divisors is an integer number (56165116000036).
Almost surely, 2112330232000071 is an apocalyptic number.
112330232000071 is a deficient number, since it is larger than the sum of its proper divisors (1).
112330232000071 is an equidigital number, since it uses as much as digits as its factorization.
112330232000071 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1512, while the sum is 25.
Adding to 112330232000071 its reverse (170000232033211), we get a palindrome (282330464033282).
The spelling of 112330232000071 in words is "one hundred twelve trillion, three hundred thirty billion, two hundred thirty-two million, seventy-one", and thus it is an aban number.
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