11234222437 has 2 divisors, whose sum is σ = 11234222438. Its totient is φ = 11234222436.

The previous prime is 11234222383. The next prime is 11234222443. The reversal of 11234222437 is 73422243211.

11234222437 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 6199042756 + 5035179681 = 78734^2 + 70959^2 .

It is a cyclic number.

It is not a de Polignac number, because 11234222437 - 2⁷ = 11234222309 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11234222399 and 11234222408.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11234222477) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5617111218 + 5617111219.

It is an arithmetic number, because the mean of its divisors is an integer number (5617111219).

Almost surely, 2^11234222437 is an apocalyptic number.

It is an amenable number.

11234222437 is a deficient number, since it is larger than the sum of its proper divisors (1).

11234222437 is an equidigital number, since it uses as much as digits as its factorization.

11234222437 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 16128, while the sum is 31.

Adding to 11234222437 its reverse (73422243211), we get a palindrome (84656465648).

The spelling of 11234222437 in words is "eleven billion, two hundred thirty-four million, two hundred twenty-two thousand, four hundred thirty-seven".