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112343004140 = 2255617150207
BaseRepresentation
bin110100010100000101…
…0100011001111101100
3101201222101011220211012
41220220022203033230
53320034302113030
6123335404244352
711054651531213
oct1505012431754
9351871156735
10112343004140
114370a773874
12199335406b8
13a794a4b0a3
14561a44807a
152dc7b61095
hex1a282a33ec

112343004140 has 12 divisors (see below), whose sum is σ = 235920308736. Its totient is φ = 44937201648.

The previous prime is 112343004127. The next prime is 112343004181. The reversal of 112343004140 is 41400343211.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2808575084 + ... + 2808575123.

It is an arithmetic number, because the mean of its divisors is an integer number (19660025728).

Almost surely, 2112343004140 is an apocalyptic number.

112343004140 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

112343004140 is an abundant number, since it is smaller than the sum of its proper divisors (123577304596).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

112343004140 is a wasteful number, since it uses less digits than its factorization.

112343004140 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5617150216 (or 5617150214 counting only the distinct ones).

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 112343004140 its reverse (41400343211), we get a palindrome (153743347351).

The spelling of 112343004140 in words is "one hundred twelve billion, three hundred forty-three million, four thousand, one hundred forty".

Divisors: 1 2 4 5 10 20 5617150207 11234300414 22468600828 28085751035 56171502070 112343004140