Base | Representation |
---|---|
bin | 10100111100000010… |
… | …00011111101101111 |
3 | 1002000101221122001122 |
4 | 22132001003331233 |
5 | 141010144404403 |
6 | 5055233531155 |
7 | 545364014645 |
oct | 123601037557 |
9 | 32011848048 |
10 | 11241013103 |
11 | 4849293581 |
12 | 2218713abb |
13 | 10a1b41658 |
14 | 788ccb195 |
15 | 45bcea838 |
hex | 29e043f6f |
11241013103 has 2 divisors, whose sum is σ = 11241013104. Its totient is φ = 11241013102.
The previous prime is 11241013099. The next prime is 11241013127. The reversal of 11241013103 is 30131014211.
It is a weak prime.
It is an emirp because it is prime and its reverse (30131014211) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11241013103 - 22 = 11241013099 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11241013193) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5620506551 + 5620506552.
It is an arithmetic number, because the mean of its divisors is an integer number (5620506552).
Almost surely, 211241013103 is an apocalyptic number.
11241013103 is a deficient number, since it is larger than the sum of its proper divisors (1).
11241013103 is an equidigital number, since it uses as much as digits as its factorization.
11241013103 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 72, while the sum is 17.
Adding to 11241013103 its reverse (30131014211), we get a palindrome (41372027314).
The spelling of 11241013103 in words is "eleven billion, two hundred forty-one million, thirteen thousand, one hundred three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •