Base | Representation |
---|---|
bin | 10100111100000011… |
… | …11110010100000111 |
3 | 1002000102101202220111 |
4 | 22132001332110013 |
5 | 141010230031403 |
6 | 5055243013451 |
7 | 545366031514 |
oct | 123601762407 |
9 | 32012352814 |
10 | 11241252103 |
11 | 48494370a4 |
12 | 221880a287 |
13 | 10a1bc6383 |
14 | 788d5030b |
15 | 45bd4656d |
hex | 29e07e507 |
11241252103 has 2 divisors, whose sum is σ = 11241252104. Its totient is φ = 11241252102.
The previous prime is 11241252101. The next prime is 11241252133. The reversal of 11241252103 is 30125214211.
11241252103 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11241252103 - 21 = 11241252101 is a prime.
Together with 11241252101, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11241252101) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5620626051 + 5620626052.
It is an arithmetic number, because the mean of its divisors is an integer number (5620626052).
Almost surely, 211241252103 is an apocalyptic number.
11241252103 is a deficient number, since it is larger than the sum of its proper divisors (1).
11241252103 is an equidigital number, since it uses as much as digits as its factorization.
11241252103 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 480, while the sum is 22.
Adding to 11241252103 its reverse (30125214211), we get a palindrome (41366466314).
The spelling of 11241252103 in words is "eleven billion, two hundred forty-one million, two hundred fifty-two thousand, one hundred three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.072 sec. • engine limits •