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112433000135 = 522486600027
BaseRepresentation
bin110100010110110000…
…1110110111011000111
3101202012122112012010012
41220231201312323013
53320230322001020
6123352341220435
711060123506211
oct1505541667307
9352178465105
10112433000135
1143756552125
121995970171b
13a7aa59b261
1456283935b1
152dd09db7c5
hex1a2d876ec7

112433000135 has 4 divisors (see below), whose sum is σ = 134919600168. Its totient is φ = 89946400104.

The previous prime is 112433000131. The next prime is 112433000143. The reversal of 112433000135 is 531000334211.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 112433000135 - 22 = 112433000131 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 112433000135.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (112433000131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11243300009 + ... + 11243300018.

It is an arithmetic number, because the mean of its divisors is an integer number (33729900042).

Almost surely, 2112433000135 is an apocalyptic number.

112433000135 is a deficient number, since it is larger than the sum of its proper divisors (22486600033).

112433000135 is an equidigital number, since it uses as much as digits as its factorization.

112433000135 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 22486600032.

The product of its (nonzero) digits is 1080, while the sum is 23.

Adding to 112433000135 its reverse (531000334211), we get a palindrome (643433334346).

The spelling of 112433000135 in words is "one hundred twelve billion, four hundred thirty-three million, one hundred thirty-five", and thus it is an aban number.

Divisors: 1 5 22486600027 112433000135