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1126444335493 is a prime number
BaseRepresentation
bin10000011001000101010…
…100001000000110000101
310222200112211202012100211
4100121011110020012011
5121423424222213433
62221251551235421
7144245224604401
oct20310524100605
93880484665324
101126444335493
113a47a4508714
1216238bb18b71
13822b9614279
143c73d5c4101
151e47c3748cd
hex10645508185

1126444335493 has 2 divisors, whose sum is σ = 1126444335494. Its totient is φ = 1126444335492.

The previous prime is 1126444335469. The next prime is 1126444335539. The reversal of 1126444335493 is 3945334446211.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 925688364129 + 200755971364 = 962127^2 + 448058^2 .

It is a cyclic number.

It is not a de Polignac number, because 1126444335493 - 25 = 1126444335461 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1126444335593) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 563222167746 + 563222167747.

It is an arithmetic number, because the mean of its divisors is an integer number (563222167747).

Almost surely, 21126444335493 is an apocalyptic number.

It is an amenable number.

1126444335493 is a deficient number, since it is larger than the sum of its proper divisors (1).

1126444335493 is an equidigital number, since it uses as much as digits as its factorization.

1126444335493 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 3732480, while the sum is 49.

The spelling of 1126444335493 in words is "one trillion, one hundred twenty-six billion, four hundred forty-four million, three hundred thirty-five thousand, four hundred ninety-three".