1130000301431 has 2 divisors, whose sum is σ = 1130000301432. Its totient is φ = 1130000301430.

The previous prime is 1130000301377. The next prime is 1130000301433. The reversal of 1130000301431 is 1341030000311.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1130000301431 is a prime.

It is a super-2 number, since 2×1130000301431² (a number of 25 digits) contains 22 as substring.

Together with 1130000301433, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1130000301433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565000150715 + 565000150716.

It is an arithmetic number, because the mean of its divisors is an integer number (565000150716).

Almost surely, 2^{1130000301431} is an apocalyptic number.

1130000301431 is a deficient number, since it is larger than the sum of its proper divisors (1).

1130000301431 is an equidigital number, since it uses as much as digits as its factorization.

1130000301431 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 108, while the sum is 17.

Adding to 1130000301431 its reverse (1341030000311), we get a palindrome (2471030301742).

The spelling of 1130000301431 in words is "one trillion, one hundred thirty billion, three hundred one thousand, four hundred thirty-one".