11300010113213 has 4 divisors (see below), whose sum is σ = 11791314900768. Its totient is φ = 10808705325660.

The previous prime is 11300010113191. The next prime is 11300010113317. The reversal of 11300010113213 is 31231101000311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11300010113213 - 2²² = 11300005918909 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11300010113191 and 11300010113200.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11300010115213) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 245652393743 + ... + 245652393788.

It is an arithmetic number, because the mean of its divisors is an integer number (2947828725192).

Almost surely, 2^{11300010113213} is an apocalyptic number.

It is an amenable number.

11300010113213 is a deficient number, since it is larger than the sum of its proper divisors (491304787555).

11300010113213 is an equidigital number, since it uses as much as digits as its factorization.

11300010113213 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 491304787554.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 11300010113213 its reverse (31231101000311), we get a palindrome (42531111113524).

The spelling of 11300010113213 in words is "eleven trillion, three hundred billion, ten million, one hundred thirteen thousand, two hundred thirteen".