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11300110213103 is a prime number
BaseRepresentation
bin1010010001110000001100…
…0011100001111111101111
31111000021120002222010000022
42210130003003201333233
52440120111203304403
640011110550552355
72244256156665665
oct244340303417757
944007502863008
1011300110213103
113667393692a18
1213260540686bb
1363c799030cca
142b0cdd1a6c35
15148e1d888d38
hexa47030e1fef

11300110213103 has 2 divisors, whose sum is σ = 11300110213104. Its totient is φ = 11300110213102.

The previous prime is 11300110213099. The next prime is 11300110213111. The reversal of 11300110213103 is 30131201100311.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 11300110213103 - 22 = 11300110213099 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11300110213003) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5650055106551 + 5650055106552.

It is an arithmetic number, because the mean of its divisors is an integer number (5650055106552).

Almost surely, 211300110213103 is an apocalyptic number.

11300110213103 is a deficient number, since it is larger than the sum of its proper divisors (1).

11300110213103 is an equidigital number, since it uses as much as digits as its factorization.

11300110213103 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 11300110213103 its reverse (30131201100311), we get a palindrome (41431311313414).

The spelling of 11300110213103 in words is "eleven trillion, three hundred billion, one hundred ten million, two hundred thirteen thousand, one hundred three".