Base | Representation |
---|---|
bin | 1010010001110000001100… |
… | …0011100001111111101111 |
3 | 1111000021120002222010000022 |
4 | 2210130003003201333233 |
5 | 2440120111203304403 |
6 | 40011110550552355 |
7 | 2244256156665665 |
oct | 244340303417757 |
9 | 44007502863008 |
10 | 11300110213103 |
11 | 3667393692a18 |
12 | 13260540686bb |
13 | 63c799030cca |
14 | 2b0cdd1a6c35 |
15 | 148e1d888d38 |
hex | a47030e1fef |
11300110213103 has 2 divisors, whose sum is σ = 11300110213104. Its totient is φ = 11300110213102.
The previous prime is 11300110213099. The next prime is 11300110213111. The reversal of 11300110213103 is 30131201100311.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11300110213103 - 22 = 11300110213099 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11300110213003) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5650055106551 + 5650055106552.
It is an arithmetic number, because the mean of its divisors is an integer number (5650055106552).
Almost surely, 211300110213103 is an apocalyptic number.
11300110213103 is a deficient number, since it is larger than the sum of its proper divisors (1).
11300110213103 is an equidigital number, since it uses as much as digits as its factorization.
11300110213103 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 54, while the sum is 17.
Adding to 11300110213103 its reverse (30131201100311), we get a palindrome (41431311313414).
The spelling of 11300110213103 in words is "eleven trillion, three hundred billion, one hundred ten million, two hundred thirteen thousand, one hundred three".
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