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1130011213103 = 11310000099231
BaseRepresentation
bin10000011100011001111…
…010101011110100101111
311000000202102110100120222
4100130121322223310233
5122003230332304403
62223041530001555
7144432505554443
oct20343172536457
94000672410528
101130011213103
113a6264963653
121630065762bb
1382737598136
143c99b1d0823
151e5da592338
hex10719eabd2f

1130011213103 has 4 divisors (see below), whose sum is σ = 1140011312448. Its totient is φ = 1120011113760.

The previous prime is 1130011213099. The next prime is 1130011213117. The reversal of 1130011213103 is 3013121100311.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1130011213103 - 22 = 1130011213099 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1130011215103) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5000049503 + ... + 5000049728.

It is an arithmetic number, because the mean of its divisors is an integer number (285002828112).

Almost surely, 21130011213103 is an apocalyptic number.

1130011213103 is a deficient number, since it is larger than the sum of its proper divisors (10000099345).

1130011213103 is a wasteful number, since it uses less digits than its factorization.

1130011213103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10000099344.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 1130011213103 its reverse (3013121100311), we get a palindrome (4143132313414).

The spelling of 1130011213103 in words is "one trillion, one hundred thirty billion, eleven million, two hundred thirteen thousand, one hundred three".

Divisors: 1 113 10000099231 1130011213103